TSTP Solution File: NUM782^1 by Duper---1.0

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% File     : Duper---1.0
% Problem  : NUM782^1 : TPTP v8.1.2. Released v3.7.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n003.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 10:57:41 EDT 2023

% Result   : Theorem 3.25s 3.61s
% Output   : Proof 3.25s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : NUM782^1 : TPTP v8.1.2. Released v3.7.0.
% 0.00/0.13  % Command    : duper %s
% 0.13/0.34  % Computer : n003.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit   : 300
% 0.13/0.34  % WCLimit    : 300
% 0.13/0.34  % DateTime   : Fri Aug 25 09:58:23 EDT 2023
% 0.13/0.34  % CPUTime    : 
% 3.25/3.61  SZS status Theorem for theBenchmark.p
% 3.25/3.61  SZS output start Proof for theBenchmark.p
% 3.25/3.61  Clause #0 (by assumption #[]): Eq (Eq x0 y0) True
% 3.25/3.61  Clause #1 (by assumption #[]): Eq (Eq y0 z0) True
% 3.25/3.61  Clause #2 (by assumption #[]): Eq (Not (Eq x0 z0)) True
% 3.25/3.61  Clause #3 (by clausification #[1]): Eq y0 z0
% 3.25/3.61  Clause #4 (by clausification #[0]): Eq x0 y0
% 3.25/3.61  Clause #5 (by forward demodulation #[4, 3]): Eq x0 z0
% 3.25/3.61  Clause #6 (by clausification #[2]): Eq (Eq x0 z0) False
% 3.25/3.61  Clause #7 (by clausification #[6]): Ne x0 z0
% 3.25/3.61  Clause #8 (by forward demodulation #[7, 5]): Ne z0 z0
% 3.25/3.61  Clause #9 (by eliminate resolved literals #[8]): False
% 3.25/3.61  SZS output end Proof for theBenchmark.p
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