TSTP Solution File: NUM782^1 by Duper---1.0
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% File : Duper---1.0
% Problem : NUM782^1 : TPTP v8.1.2. Released v3.7.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n003.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 10:57:41 EDT 2023
% Result : Theorem 3.25s 3.61s
% Output : Proof 3.25s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : NUM782^1 : TPTP v8.1.2. Released v3.7.0.
% 0.00/0.13 % Command : duper %s
% 0.13/0.34 % Computer : n003.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 300
% 0.13/0.34 % DateTime : Fri Aug 25 09:58:23 EDT 2023
% 0.13/0.34 % CPUTime :
% 3.25/3.61 SZS status Theorem for theBenchmark.p
% 3.25/3.61 SZS output start Proof for theBenchmark.p
% 3.25/3.61 Clause #0 (by assumption #[]): Eq (Eq x0 y0) True
% 3.25/3.61 Clause #1 (by assumption #[]): Eq (Eq y0 z0) True
% 3.25/3.61 Clause #2 (by assumption #[]): Eq (Not (Eq x0 z0)) True
% 3.25/3.61 Clause #3 (by clausification #[1]): Eq y0 z0
% 3.25/3.61 Clause #4 (by clausification #[0]): Eq x0 y0
% 3.25/3.61 Clause #5 (by forward demodulation #[4, 3]): Eq x0 z0
% 3.25/3.61 Clause #6 (by clausification #[2]): Eq (Eq x0 z0) False
% 3.25/3.61 Clause #7 (by clausification #[6]): Ne x0 z0
% 3.25/3.61 Clause #8 (by forward demodulation #[7, 5]): Ne z0 z0
% 3.25/3.61 Clause #9 (by eliminate resolved literals #[8]): False
% 3.25/3.61 SZS output end Proof for theBenchmark.p
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